WitrynaCalculus. Evaluate the Integral integral of x^ (-1/3) with respect to x. ∫ x−1 3 dx ∫ x - 1 … WitrynaHow do you write 1.5×10−3 in standard notation? 0.0015 Explanation: Standard …

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Witryna1.2K views 1 year ago Integration - Logarithmic Rule and Exponentials. Evaluate the … WitrynaCalculus Evaluate the Integral integral of 1/ (3x-1) with respect to xdx ∫ 1 3x − 1 dxdx ∫ 1 3 x - 1 d x d x Let u = 3x−1 u = 3 x - 1. Then du = 3dx d u = 3 d x, so 1 3du = dx 1 3 d u = d x. Rewrite using u u and d d u u. Tap for more steps... ∫ 1 u ⋅ 1 3dudx ∫ 1 u ⋅ 1 3 d u d x Simplify. Tap for more steps... ∫ 1 3ududx ∫ 1 3 u d u d x dainton brewhouse

Ex 7.4, 5 - Integrate 3x / 1 + 2x4 - Chapter 7 Class 12 - Ex 7.4

WitrynaThe value of ∫ 8+3x−x 2dx is equal to A 32sin −1( 412x−3)+C B 23sin −1( 412x−3)+C C 411 sin −1( 412x−3)+C D sin −1( 412x−3)+C Hard Solution Verified by Toppr Correct option is D) Let l=∫ 8+3x−x 2dx dx =∫ −[x 2−3x+(23)2−(23)2]+81 dx =∫ 8+ 49−(x− 23)2dx =∫ ( 2 41)2−(x− 23)2dx =sin −1⎝⎜⎜⎜⎛ 2 41x− 23⎠⎟⎟⎟⎞+C=sin −1( 412x−3)+C. … Witryna30 mar 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo. WitrynaCalculus Evaluate the Integral integral of 1/ (3x-1) with respect to xdx ∫ 1 3x − 1 dxdx … daintith transport